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PGCIL DT Electrical 13 Aug 2021 Official Paper (NR I)

Option 2 : 992

__Method 1__:

The largest three-digit number is 999

If we divide 999 with 8 we get a reminder of 7.

This indicates that 999 is 7 more than the lagest 3 digit number 999.

Hence the required largest three-digit number that will be a multiple of 8 will be:

999 – 7 = 992.

∴ 992 is the correct answer.

__Method 2__:

In general, we know that 1000 is divisible by 8. This is because the last 3-digits are zero. (According to **Divisibility Formula**).

But 1000 is not a 3 digit number.

∴ The next smaller number number that will be a multiple of 8 will be obtained by simply subtracting 8 from 1000, i.e. 1000 – 8 = 992.

∴ 992 is the correct answer.